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数学
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(1/8+1/24+1/48+1/80+1/120+1/168+1/224+1/228)*128 第二题:2005个9*2005个9+1 2005个9
人气:243 ℃ 时间:2020-05-30 18:36:24
解答
(1/8+1/24+1/48+1/80+1/120+1/168+1/224+1/288)*128
=[1/8+1/2(1/4-1/6+1/6-1/8+1/8-1/10+1/10-1/12+1/12-1/14+1/14-1/16+1/16-1/18)]*128
=[1/8+1/2*(1/4-1/18)]*128
=128*1/8+128*1/2*1/4-128*1/2*1/18
=16+16-32/9
=32又9分之8
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(1/8+1/24+1/48+1/80+1/120+1/168+1/224+1/228)*128
(1/8+1/24+1/48+1/80+1/120+1/168+1/224+1/288)*128
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