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已知x/y=1/2,求2x/(x²-2xy+y² )* (x²-y²/x+y)+2y/x-y
人气:395 ℃ 时间:2020-05-12 20:09:10
解答
x/y=1/2y=2x2x/(x²-2xy+y² )* (x²-y²/x+y)+2y/x-y=2x/(x-y)²*(x+y)(x-y)/(x+y)+2y/(x-y)=2x/(x-y)+2y/(x-y)=2(x+y)/(x-y)=2(x+2x)/(x-2x)=6x/-x=-6
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