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(1²/2002-2²/2002+.13²/2002-14²/2002+15²/2002
人气:190 ℃ 时间:2020-04-22 12:38:14
解答
(1²/2002-2²/2002+.13²/2002-14²/2002+15²/2002=(1²-2²+3²-4²+.+13²-14²+15²)/2002=(1+(3-2)(3+2)+(5-4)(5+4)+.+(15-14)(15+14))/2002=(1+2+3+...+1...
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