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△ABC中,证明( b-c )sinA+( c-a )sinB+( a-b )sinC = 0
人气:164 ℃ 时间:2019-11-14 01:49:48
解答
利用正弦定理:a / sinA = b / sinB = c / sinC = 2R(R为三角形外接圆的半径)所以:sinA = a / 2RsinB = b / 2RsinC = c / 2R代入,得:( b-c )sinA+( c-a )sinB+( a-b )sinC= (b - c)*a / 2R + (c - a)*b / 2R + (...
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