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已知a²+b²-4a-2b+5=0,求√a+√b/√2b-√a-b
人气:172 ℃ 时间:2020-04-03 11:13:49
解答
a²+b²-4a-2b+5=0(a²-4a+4)+(b²-2b+1)=0(a-2)²+(b-1)²=0a=2 b=1√a+√b/√2b-√a-b=(√2+√1)/(√2-√2-1)=(√2+1)/(√2-1)=(√2+1)²/(√2+1)(√2-1)=(2+2√2+1)/(2-1)...
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