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已知二次函数f(x)满足f(x+1)+f(x-1)=2x^2-4x,求f(x)的解析式并求函数的值域.
人气:394 ℃ 时间:2019-11-10 19:42:49
解答
f(x)=ax²+bx + cf(x+1) = a(x+1)² + b(x+1) +c = ax² + (2a+b)x + a +b+ cf(x-1) = a(x-1)² + b(x-1) + c = ax² + (b -2a)x + a -b+ cf(x+1)+f(x-1) = 2ax² + 2bx + 2(a+c) = 2x²...
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