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待定系数法因式分解:(1)x方+2xy+y方+x+y-2 (2)x方+xy-2y方+2x+7y-3
人气:314 ℃ 时间:2019-08-18 14:46:50
解答
(1)x方+2xy+y方+x+y-2
=(x+y)²+(x+y)-2
=(x+y+2)(x+y-1)
(2)x方+xy-2y方+2x+7y-3
=(x+2y)(x-y)+2x+7y-3
=(x+2y-1)(x-y+3)
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