y=(sinx-xcosx)/(cosx+xsinx)的导数
人气:251 ℃ 时间:2019-11-14 02:38:22
解答
(sinx-xcosx)'=(sinx)'-(xcosx)'
=cosx-x'*cosx-x*(cosx)'
=cosx-cosx+xsinx
=xsinx
(cosx+xsinx)'
=(cosx)'+(xsinx)'
=-sinx+x'*sinx+x*(sinx)'
=-sinx+sinx+xcosx
=xcosx
所以y'=[(sinx-xcosx)'(cosx+xsinx)-(sinx-xcosx)(cosx+xsinx)']/(cosx+xsinx)²
=[xsinx(cosx+xsinx)-xcosx(sinx-xcosx)]/(cosx+xsinx)²
=(xsinxcosx+x²sin²x-xsinxcosx+xcos²x/(cosx+xsinx)²
=x²/(cosx+xsinx)²
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