求导f(x)=e^(-3x+2)
另f(X)=1/(x-1) ,f(x)=(x^2)/(x+1)^0.5 的导数
人气:307 ℃ 时间:2020-04-07 12:38:22
解答
f(x)=e^(-3x+2)f'(x)=e^(-3x+2)'=e^(-3x+2)*(-3x+2)'=-3e^(-3x+2)f(X)=1/(x-1)f'(x)=-1/(x-1)^2*(x-1)'=-1/(x-1)^2f(x)=(x^2)/(x+1)^0.5用公式(u/v)'=(u'v-uv')/v^2f'(x)=(2x*(x+1)^0.5-x^2/(2(x+1)^0.5 ))/(x+1)
推荐
猜你喜欢