x1+x2=2x1x2=-m^2+2/3m由x1^2+x2^2-2(x1+x2)=0化为(x1+x2)^2-2x1x2-2(x1+x2)=0代入得：4-2(-m^2+2/3m)-4=0得m(m-2/3)=0m=0或2/3m=0时,原方程为x^2-2x=0,得x=0,2m=2/3时,原方程为x^2-2x=0,也得到x=0,2...�����жϸ÷��̸�����