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已知x=2003,y=2004,则(x+y)*(x^2+y^2)/(x^4-y^4)=
人气:153 ℃ 时间:2019-09-24 05:04:50
解答
(x+y)*(x^2+y^2)/(x^4-y^4)
=(x+y)(x^2+y^2)/[(x^2+y^2)(x+y)(x-y)]
=1/(x-y)
=1/(2003-2004)
=-1
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