(2x+3y)/2=(3x+2y)/5+2 ①3(2x+3y)/2=2(3x+2y)/5+6 ②
①得,2x+3y=2(3x+2y)/5+4③
代入②得,3（3x+2y)/5+6=2(3x+2y)/5+6
3x+2y=0
x=-2y/3④
代入③得,-4y/3+3y=4
y=12/5
代入④,得x=-8/5
∴方程组的解是：
x=-8/5
y=12/5


其实,加减法和整体思想-----最简单