(（x-1）/(x-3)-(x-4)/x)÷(x+3)(x-2)/x(x+3)
=(x²-x-(x-4)(x-3))/x(x-3)×x/(x-2)
=6(x-2)/x(x-3)×x/(x-2)
=6/(x-3);
x=1或x=2；
原式=-3或6；
如果本题有什么不明白可以追问,