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1.化简[(bc-a^2)/ab]+[(ac-b^2)/bc]+[(ab-c^2)/ac]
2.[(a^2-1)/a^2-5a+6]÷[x/(x^2-4)]其中x=-3
人气:298 ℃ 时间:2020-05-26 18:09:47
解答
1 =(bc^2-a^2c+a^2c-ab^2+ab^2-bc^2)/abc=0
2 (a+1)(a-1)/(a-2)(a-3)÷[x/(x+2)(x-2) 都是x?2..[(a^2-1)/a^2-5a+6]÷[(a^2+a-2)/a-3]-[(a+3)/(a^2-4)]2 =(a+1)(a-1)/(a-2)(a-3) X (a-3)/((a+2)(a-1) -(a+3)/(a+2)(a-2) =(a+1)/(a+2)(a-2) - (a+3)/(a+2)(a-2)=-2/(a+2)(a-2)=2/(4-a^2)
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