是解方程吧?
7/(x²+x)+1/(x²-x)=6/(x²-1)
7/[x(x+1)]+1/[x(x-1)]=6/[(x-1)(x+1)] 等式两边同乘以x(x-1)(x+1)
7(x-1)+(x+1)=6x
x=3
代入原方程验证：x=3是原方程的根