3a∧3+5a∧2-2
=(3a^3+3a^2)+(2a^2-2)
=3a^2(a+1)+2(a^2-1)
=3a^2(a+1)+2(a+1)(a-1)
=(a+1)[3a^2+2(a-1)]
=(a+1)(3a^2+2a-2)