先化简再求值:【1/(x-y)-1/(x+y)】÷(xy²)/(x²-y²),其中x=1-根号2,y=1+根号2
人气:208 ℃ 时间:2019-08-20 06:06:04
解答
【1/(x-y)-1/(x+y)】÷(xy²)/(x²-y²)=[1/(x-y)-1/(x+y)]×(x+y)(x-y)/(xy²)=(x+y)/(xy²-(x-y)/(Xy²)=(x+y-x+y)/(xy²)=2/(xy)当x=1-√2,y=1+√2时原式=2/[(1-√2)(1+√2)]=...
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