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解方程x^2+(200+0.5x)^2=4X^2
人气:494 ℃ 时间:2020-05-06 07:28:26
解答
x^2+(200+0.5x)^2=4X^2(200+0.5x)^2-3x^2=0(200+0.5x+√3x)(200+0.5x-√3x)=0200+(0.5+√3)x=0 200+(0.5-√3)x=0x1=-200/(0.5+√3) =800 (0.5-√3)/11x2=-200/(0.5-√3) = 800 (0.5+√3)/11
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