x^4-3x^3+4x^2-6x+4=0怎样因式分解?
人气:251 ℃ 时间:2019-09-30 20:41:40
解答
x^4-3x^3+4x^2-6x+4=0(x⁴-3x³+2x²)+(2x²-6x+4)=0x²(x²-3x+2)+2(x²-3x+2)=0(x²-3x+2)(x²+2)=0(x-1)(x-2)(x²+2)=0因为x²+2恒>0所以原方程的...
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