tana=-1/2,tan(a-b)=-2/5,则tanb=?
人气：484 ℃ 时间：2020-04-05 15:32:42
解答
tanb=tan[(a-b)-a]
=[tan(a-b)-tana]/[1+tan(a-b)tana]
=[(-2/5)-(1/2)]/[1+(2/5)*(1/2)]
=(-9/10)/(12/10)
=-9/12
=-3/4
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