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(-x^2y^m)^2*(kx^n+1y)=-2x^6y^3,则(k^m)^n=多少
人气:266 ℃ 时间:2020-10-01 18:27:30
解答
(-x^2y^m)^2*(kx^n+1y)
=x^4y^2m*(kx^n+1y)
=kx^(n+5)*y^(2m+1)
=-2x^6y^3,
k=-2,n+5=6,2m+1=3
m=n=1
(k^m)^n=k=-2
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