3.6gCaCO3中含Ca的质量是:40/100*3.6=1.44g
剩余固体的质量=1.44/57.6%=2.5g
生成CO2的质量：3.6g-2.5g=1.1g
设mCaO=x
CaCO3=高温=CaO+CO2
````````````````````x``1.1g
````````````````````56``44
x/56=1.1g/44
x=1.4
答：生成氧化钙的质量为1.4g