y=(sin2x)^2+sin2xcos2x=(1-cos4x)/2+1/2*sin4x=(sin4x-cos4x+1)/2=[√2sin(4x-π/4)+1]/2最大值为(√2+1)/2,当4x-π/4=2kπ+π/2,即x=kπ/2+3π/16时取最大值最小值为(-√2+1)/2,当4x-π/4=2kπ-π/2,即x=kπ/2-π/...