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sin(90°+c)+sinc=
人气:333 ℃ 时间:2020-09-30 20:07:10
解答
sin(90°+c)+sinc
=cosc+sinc
=√2(√2/2cosc+√2/2sinc)
=√2(sinccosπ/4+coscsinπ/4)
=√2sin(c+π/4)
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