> 数学 >
若x,y,z满足3x+7x+z=1,4x+10y+z=2006,求分式2005x+2005y+2005z/x+3y的值
人气:237 ℃ 时间:2020-08-13 11:21:30
解答
3x+7x+z=1 ①
4x+10y+z=2006 ②
②-①得
x+3y=2005 ③
①乘以3得
9x+21y+3z=3 ④
②乘以2得
8x+20y+2z=4012 ⑤
④-⑤得
x+y+z=-4009
所以所求式子
=2005(x+y+z)/(x+3y)
=2005*(-4009)/2005
=-4009
推荐
猜你喜欢
© 2026 79432.Com All Rights Reserved.
电脑版|手机版