(1)f(x)= [cos(x-π/6)]^2 - (sinx)^2f(π/12) = (cos(π/12))^2 - (sin(π/12))^2=cos(π/6)=√3/2(2)f(x) =[cos(x-π/6)]^2 - (sinx)^2= [(√3/2)cosx + (1/2)sinx]^2 - (sinx)^2= (1/4)( 3(cosx)^2 + 2√3sinxcos...