b²-4ac=（2m-1）²-4m²=-4m＋1≥0m≤1/4∵x1²-x2²=（x1-x2）（x1＋x2）=0①当x1＋x2=0时,x1＋x2=1-2m=0 m=1/2②当x1-x2=0时,x1=x2 b²-4ac=0∴-4m＋1=0 m=1/4综上所得：当m=1/4时,满足...