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数学
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lg2*lg50+lg25-lg5*lg20
需要过程,谢谢~
人气:376 ℃ 时间:2020-03-26 04:42:12
解答
lg2*lg50+lg25-lg5*lg20
=lg2(lg5+lg10)+lg25-lg5(lg2+lg10)
=lg2(lg5+1)+lg25-lg5(lg2+1)
=lg2lg5+lg2+lg25-lg2lg5-lg5
=lg2+lg25-lg5
=lg(2×25÷5)
=lg10
=1
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