一个简单的无穷小问题...limx→0(1-cosx)/x^2=1/2 \
人气:326 ℃ 时间:2020-06-08 22:15:18
解答
1-cosx=1-(1-2sin(1/2x)^2)=2sin(1/2x)^2limx->01-cosx=limx->02sin(1/2x)^2 =limx->02(1/2x)^2 =2×1/4x^2 =1/2x^2limx→0(1-cosx)/x^2=1/...1-cosx是等于2sin(x/2)^2还是2sin(1/2x)^2呢??错了,应该是1-cosx=1-[1-2sin²(x/2)]=2sin²(x/2)
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