最小值 = 2(- 1) + 1 = - 1
最大值 = 2(1) + 1 = 3
值域为[- 1,3]谢谢，不过我题目掉了一个条件，x∈﹙0，π/4﹚.对不起啊。1 + 2sin(2x - π/3)在0≤x≤π/4上单调递增最小值为f(0) = 2sin(- π/3) + 1 = - √3 + 1最大值为f(π/4) = 2sin(2 * π/4 - π/3) + 1 = 2值域为[1 - √3，2]