先用一个等式(n+1)/(k+1)C(k,n)=C(k+1,n+1)证明：C(k+1,n+1)/C(k,n)=[(n+1)!/(k+1)!*(n-k)!]/[n!/k!*(n-k)!]=(n+1)/(k+1)所以1/(k+1)C(k,n)=1/(n+1)C(k+1,n+1)所以Cn0+1/2Cn1+1/3Cn2+...+1/（n+1）Cnn=1/(n+1)*[C(1,...