∵6mx²-8nxy+3x-4xy-x²+y-3
=(6m-1)x²+(-8n-4)xy+3x+y-3
要使此多项式不含二次项,
则
6m-1=0,-8n-4=0
∴m=1/6,n=-½
∴3m-4n=3×(1/6)-4×(-½)
=½+2
=5/2