证明：3^x = 4^y = 6^z3^x = 2^2y = (2^z)*(3^z)(3^x)*(2^2y) = (2^z)*(3^z)*(2^z)*(3^z)(3^x)*(2^2y) = (2^2z)*(3^2z)因为“ 3^n ”永远为奇数,“ 2^n ”永远为偶数所以 3^x=3^2z,2^2y=2^2z,即 x=2z,2y=2z 变成 1/(...