化简求值:2xy^2-[3xy^2-2(x^2y-(1/2)xy^2)]-2x^2y其中x=-2/3,y=-1/2
人气:470 ℃ 时间:2019-12-08 13:16:56
解答
2xy^2-[3xy^2-2(x^2y-(1/2)xy^2)]-2x^2y
=2xy²-[4xy²-2x²y]-2x²y
=2xy²﹣4xy²﹢2x²y﹣2x²y
=﹣2xy²
=﹣2×﹙﹣2/3﹚﹙﹣1/2﹚
=﹣2/3﹣2×﹙﹣2/3﹚﹙﹣1/2﹚(﹣1/2﹚不是平方吗漏了2xy^2-[3xy^2-2(x^2y-(1/2)xy^2)]-2x^2y=2xy²-[4xy²-2x²y]-2x²y=2xy²﹣4xy²﹢2x²y﹣2x²y=﹣2xy²=﹣2×﹙﹣2/3﹚﹙﹣1/2﹚²=1/3
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