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1/2xy-{1/2xy-[1/3x^2y-(x^2y-xy)]+1/3x^2y}
这是计算题,
人气:174 ℃ 时间:2019-10-19 00:23:57
解答
原式=1/2xy-{1/2xy-[1/3x^2y-x^2y+xy]+1/3x^2y} &&去小括号=1/2xy-{1/2xy-[-2/3x^2y+xy]+1/3x^2y}=1/2xy-{1/2xy+2/3x^2y-xy+1/3x^2y} &&去中括号=1/2xy-{-1/2xy+x^2y}=1/2xy+1/2xy-x^2y &&去大括号=xy-x^2y...
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