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已知3sin(-5∏-A)=4cos(A-6∏),求2sin^2A+sinA*cosA-3cos^2A之值?急,
人气:347 ℃ 时间:2020-10-01 22:13:48
解答
∵3sin(-5π-A)=4cos(A-6π)
∴3sinA=4cosA
∴tana=4/3
∵2sin^2A+sinA*cosA-3cos^2A
=(2sin^2A+sinA*cosA-3cos^2A)/(sin^2A+cos^2A)
=(2tan^2A+tanA-3)/(tan^2A+1)
=(2×16/9+4/3-3)/(16/9+1)
=17/25
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