xy²+2xy-3x-y²+2y-1因式分解
人气:270 ℃ 时间:2019-07-22 14:25:46
解答
xy²+2xy-3x-y²+2y-1
=x(y²+2y-3)-(y²-2y+1)
=x(y+3)(y-1)-(y-1)²
=(y-1)[x(y+3)-(y-1)]
=(y-1)(xy+3x-y+1)
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