设圆心为(a,b),半径为R,
则(a-2)^2+(b-2)^2=(a-3)^2+(b+1)^2=(a-5)^2+(b-3)^2=R^2,
解得：a=4,b=1,R^2=5,
∴圆方程为(X-4)^2+(Y-1)^2=5.