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数学
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因式分解2a(a-4)^2-6a^2(4-a)+8a(a-4a)
人气:102 ℃ 时间:2020-04-23 09:32:21
解答
2a(a-4)^2-6a^2(4-a)+8a(a-4a)
=2a(a-4)^2+6a^2(a-4)+8a^2(a-4)
=2a(a-4)^2+14a^2(a-4)
=2a(a-4)(a-4+7a)
=2a(a-4)(8a-4)
=8a(a-4)(2a-1)
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