方程组 {5x+8y+12z=100 x+y+z=14
方程组
{5x+8y+12z=100
x+y+z=14
人气:434 ℃ 时间:2020-05-19 18:30:50
解答
会有无限多组解.
5x + 8y = 100 - 12z
x + y = 14 - z → 5x + 5y = 70 - 5z
3y = 30 - 7z
y = 10 - (7/3)z
x = 4 + (4/3)z = 4(1 + z/3)
若设x = 4n
z = 3n - 3
y = 10 - (7/3)(3n - 3) = 17 - 7n
所以解为:
x = 4n
y = 17 - 7n
z = 3n - 3
n为任意整数
推荐
猜你喜欢
- 这个禤字是怎样读的
- 括号前面是减号,脱括号要变号.那下面的要不要变号
- I don't play basketball any more,________when I was child.A.but I used to B,but I used to do .选
- 1支铅笔,2块橡皮,3个卷笔刀共花了5.3元,2支铅笔,3块橡皮,4个卷笔刀用了7.7元,3支铅笔,3块橡皮,5个
- like,guess,give,fly,tell,teach,ake,carry,play,catch,ride,study,want,watch,write,find,go,do的动词第三人称单数形式?
- 浓盐酸与稀盐酸及稀硫酸的具体区别?
- 求一句大概概括关于美国人对时间观念的英语句子.
- 因式分解c^2 - 1+ 2ab - a^2 b^2