f(x)=(cos²wx-sin²x)+2√3coswxsinwx
=cos(2wx)+√3sin(2wx)
=2sin(2wx+π/6)
1,相邻两对称轴之间的距离为π/2,
说明f(x)的最小正周期T=2×(π/2)=π
而T=2π/(2w)=π/w,所以w=1
那么f(x)=2sin(2x+π/6)
2,f(A)=2sin(2A+π/6)=1
所以sin(2A+π/6)=1/2
而0