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函数y=cos(cosx+sinx)的最小正周期是?
人气:249 ℃ 时间:2020-01-29 13:31:07
解答
y=cos²x+sinxcosx
=(1+cos2x)/2+1/2*sin2x
=(1/2)(sin2x+cos2x)+1/2
=(√2/2)(√2/2*sin2x+√2/2cos2x)+1/2
=(√2/2)(sin2xcosπ/4+cos2xsinπ/4)+1/2
=(√2/2)sin(2x+π/4)+1/2
T=2π/2=π
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