2x = y²,(1/2,- 1) → (0,0)；(0,0) → (2,2)対于X型区间：路径1：x = 1/2 → x = 0,y = - √(2x),dy/dx = - 1/(√2√x)路径2：x = 0 → x = 2,y = √(2x),dy/dx = 1/(√2√x)∫_(1) xy ds= ∫(0→1/2) - x√(2...