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数学
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设实数x,y满足x2+y2=1则 xy的取值范围是?
设实数x,y满足x2+y2=1则 xy的取值范围是________.
人气:162 ℃ 时间:2019-10-10 06:39:58
解答
由基本不等式得x2+y2>=2根号(x2y2)=2丨xy丨,即2丨xy丨
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