> 数学 >
y=sin(x-π/6)sin(x+π/3)最小正周期
人气:201 ℃ 时间:2019-12-06 18:35:35
解答
y=sin(x-π/6)sin(x+π/3)
=-cos(x-π/6+π/2)sin(x+π/3)
=-cos(x+π/3)sin(x+π/3)
=-sin(2x+2π/3)/2
T=2π/2=π
推荐
猜你喜欢
© 2025 79432.Com All Rights Reserved.
电脑版|手机版