x²+px+q<0的解集是{x|-1/2<x<1/3}说明：x²+px+q=0的两根是：-1/2,1/3,根据韦达定理：得：-p=-1/2+1/3=-1/6p=1/6q=-1/2(1/3)=-1/6qx²+px+1>0-(1/6)x²+(1/6)x+1>0两边同乘以-...