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已知tanx 2 则sin^2x-sinxcosx
人气:162 ℃ 时间:2020-04-09 01:10:01
解答
sin^2x-sinxcosx
=(sin^2x-sinxcosx)/(sin^2x+cos^2x) (上下同除以cos^2x)
=(tan^2x-tanx)/(tan^2x+1)
=2/5
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