∵ cos2x=2cos²x-1∴ cos²x=(cos2x+1)/2∵ sin2x=2sinxcosx∴ f(x)=√3sinxcosx-cos²x+1/2=√3/2sin2x-1/2cos2x-1/2+1/2=√3/2sin2x-1/2cos2x=sin2xcosπ/6-sinπ/6cos2x=sin(2x-π/6)(1) 函数f(x)的...