x1^2+x1x2+x2^2
=(x1+x2)²-2x1x2+x1x2
=(x1+x2)²-x1x2
=p-q=3/2
1/x1^+1/x2^
=(x1^2+x2^2)/(x1x2)²
=[(x1+x2)²-2x1x2]/(x1x2)²
=(p-2q)/q²=5/2
两式联立,解得：
p=1/2 q=-1
或p=21/10 q=3/5p-q=3/2=(p-2q)/q²=5/2请问怎么解呢?(p-2q)/q2=[(p-q)-q]/q2=(3/2-q)/q2=5/2整理得：5q2-2q+3=0(5q-3)(q+1)=0即q=3/5或q=-1懂了。谢谢