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x²-64y²分之2x 减 x-8y分之1
人气:331 ℃ 时间:2020-05-23 16:04:45
解答
2x/(x²-64y²) - 1/(x-8y) 根据公式:a²-b²=(a+b)(a-b)
=2x/(x+8y)(x-8y) - 1/(x-8y) 通分
=2x/(x+8y)(x-8y) - (x-8y)/(x+8y)(x-8y)
=(2x-x+8y)/(x+8y)(x-8y)
=(x+8y)/(x+8y)(x-8y)
=1/(x-8y)
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